php – ajax data insert

This tutorial is posted for beginners as well as experienced developers. It will help you insert form data into the MySQL Database without page refresh.

<body>

<!– form start –>

<div class="card">
<div id="notification" style="padding:10px; color:white"></div><br/>
<div class="container" style="padding:20px">

<h3>Login Form</h3><br/>

<div class="form-group">
<label>Username</label>
<input type="text" id="username" class="form-control" />
<span id="msg1" style="color:red"></span>
</div>

<div class="form-group">
<label>Password</label>
<input type="text" id="password" class="form-control" />
<span id="msg2" style="color:red"></span>
</div>

<button type="button" class="btn btn-success" id="submitbtn">Submit</button><br/><br/>

<div class="preview">
<img id="preview-selected-image" />
</div>

</div>
<br/>

</div>


<!–  code for insert data –>
<script type="text/javascript">

$(document).ready(function(){
//  alert('hi');
$(document).on('click','#submitbtn',function(){
var username = document.getElementById('username');
var password = document.getElementById('password');

$.ajax({
url:'submit.php',
method:'POST',
data:{Username: username, Password: password},
beforeSend:function(){
$('#submitbtn').html('Loading…');
$('#submitbtn').css('background', '#ccc');
$('#submitbtn').css('border', 'none');
$('#submitbtn').css('pointer-events', 'none');
},

success:function(data){
// alert('hi');

if(data == 504){
$('#notification').show();
}
else{

}

}

});

});

});

</script>


<!–  code for fetch data –>

<script type=”text/javascript”>

$(document).ready(function(){
function ajaloadlogo(){

$.ajax({
url:'fetch_partner_logo.php',
type:'POST',
success:function(data){
$('#logo_load').html(data);
}

});

}

ajaloadlogo();

});

</script>

<tbody id="logo_load">
</tbody>

</body>

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